Lupita confirms Kenya visit, dinner
25 June 2015, 18:47
Nairobi - Oscar winning actress Lupita Nyong'o will hold a dinner at a posh Nairobi Hotel to aid Wildlife Conservation, she has announced.
Lupita will be the chief guest at an exclusive conservation function which
will be held on Thursday, July 2 at the Villa Rosa Kempinski Nairobi.
The function is aimed at raising support for elephants as the
endangered animals are increasingly being targeted for their ivory.
" I am delighted to be returning home, especially with the added honor
of being able to use this opportunity to help shine a global light on
Kenya’s conservancy efforts," said Nyongo.
" Our country’s elephants are a critical piece of the heart of
Kenya and we need to take action now to save their population from the
threats that continue to endanger their existence," she added.
Lupita will partner with WildAid, whose mission is to end the sale
of illegal wildlife artifacts such as elephant tusks or rhino horns.
Entrance to the event will be KES 10,000 or 100,000 per table which will go directly to aid the conservation efforts.
For the latest on national news, politics, sport, entertainment and more follow us on Twitter and like our Facebook page!
Disclaimer: All articles and letters published on MyNews24 have been independently written by members of News24's community. The views of users published on News24 are therefore their own and do not necessarily represent the views of News24. News24 editors also reserve the right to edit or delete any and all comments received.